D

Hence,

Considering the moment equilibrium at joint B,

^ Mb = Mba + Mbc = 0 Substituting for MBA and MBC one obtains

— (1O0B + 20C - 9C) = 240 or 11O0B + 20C - 9C = 2160 (2.29)

9 EI

considering the moment equilibrium at joint c,

Substituting for MCB and MCD we get

2EI (40c + 0b - 2C) = -120 or 0b + 40c - 2C = -540 (2.30)

9 EI

If summation of the base shear equals zero, we have

Substituting for MAB, MBA, MCD, and MDC and simplifying

solution of Equations 2.29 to 2.31 results in

B EI

0 0

Post a comment