Solution

(6)(12) + (5)(1) + (2)(16) + (1)(14) = 123 g/gmol at 4°C),

UAD.2 CHEMICAL CONVERSIONS

Applying conversion factors,

30.48 cm

5. The cross-sectional area of the base is calculated as:

Since there are 454g/lb,

Using Newton's law, the force exerted by the mass is

F = m(^j = (O.llOlb)^l^ = 0.1101bf Note that, in the English system, g = 32.2 ft/s2 go = 32.2-

Since the force is exerted over an area of 0.78 in.2, the pressure at the base

By definition:

Thus,

P _p _ p gauge 1 absolute 1 atmospheric

6. There are 6.02 x 1023 (Avogadro's number) molecules/gmol. Therefore,

(0.406 gmol)(6.02 x 1023 molecules/gmol) = 2.44 x 1023 molecules

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