Solution

(6)(12) + (5)(1) + (2)(16) + (1)(14) = 123 g/gmol at 4°C),

UAD.2 CHEMICAL CONVERSIONS

Applying conversion factors,

30.48 cm

5. The cross-sectional area of the base is calculated as:

Since there are 454g/lb,

Using Newton's law, the force exerted by the mass is

F = m(^j = (O.llOlb)^l^ = 0.1101bf Note that, in the English system, g = 32.2 ft/s2 go = 32.2-

Since the force is exerted over an area of 0.78 in.2, the pressure at the base

By definition:

Thus,

P _p _ p gauge 1 absolute 1 atmospheric

6. There are 6.02 x 1023 (Avogadro's number) molecules/gmol. Therefore,

(0.406 gmol)(6.02 x 1023 molecules/gmol) = 2.44 x 1023 molecules

Do It Yourself Car Diagnosis

Do It Yourself Car Diagnosis

Don't pay hundreds of dollars to find out what is wrong with your car. This book is dedicated to helping the do it yourself home and independent technician understand and use OBD-II technology to diagnose and repair their own vehicles.

Get My Free Ebook


Post a comment