R3 r2 Pwggcz2z3

= 95,771 + (1000)(9.807)(9.0/3.281) = 122,673 Pa (gauge) = 122,673/101,325 = 1.2 atm (gauge)


The pressure force at the bottom of the tank is then

= (122,673 + 101,325)(7i)(6.1)2/4 = 6,537,684 N = (6,537,684)(0.2248) = 1,469,671 lbf

To calculate the force on the side of the tank within the water layer, one needs to first obtain an equation of the variation of pressure with height in the water layer:

The total force is then obtained by an integration since the pressure varies with height.

Z3 = -13.72m (-45 ft) and Z2 = -10.98m(-36ft) F = 6.14-11,910(—10.98 + 13.72) + 4903.5(10.982 - 13.722)] = 5.73 x 106N

Calculations of fluid pressure force on submerged surfaces is important in selecting the proper material and thickness. If the pressure on the submerged surface is not uniform, then the pressure force is calculated by integration. Also note that a nonmoving, simple fluid exerts only pressure forces; moving fluids exert both pressure and shear forces.

Do It Yourself Car Diagnosis

Do It Yourself Car Diagnosis

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